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Inorganic Chemistry

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A spoken answer, marked

An examiner's question, answered out loud and marked criterion by criterion. From Inorganic Chemistry Viva Questions: A Practical Guide.

Oral — Spin state in an iron complexMarked

Examiner

For [Fe(CN)6]4−, assign the iron oxidation state and d-electron count, then predict the spin state and magnetic behaviour.

2:363:00Mark answer
77%Spin state in an iron complex — marked77/100 · Developing · 2:36 spoken of 3:00
Charge and oxidation-state reasoning18/20

Correctly used the six cyanide charges and overall charge to assign Fe(II).

ImproveSay explicitly that Fe(II) is d6 before describing the orbital filling.

Ligand-field explanation15/20

Identified cyanide as strong field and gave the low-spin arrangement, but did not clearly name both orbital sets at first.

ImproveState t2g6 eg0 and connect it to the octahedral field.

Prediction and conclusion13/20

Predicted diamagnetism but initially gave no direct link to the number of unpaired electrons.

ImproveFinish with: all six electrons are paired, so the complex is diamagnetic.

A strong answerEach cyanide ligand has a charge of −1, so six ligands contribute −6. The overall charge is −4, which means iron is in the +2 oxidation state. Fe(II) is d6, and in an octahedral strong field from cyanide the low-spin arrangement is t2g6 eg0. There are no unpaired d electrons, so the complex is predicted to be diamagnetic.

An illustrative marked viva showing a sound answer that needs a more explicit link between electron arrangement and magnetism.
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