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Organic Chemistry

3 guides for this subject — how to prepare, what to practise, and how to know it has gone in.

A practice question

Choose an answer and it is marked, with the explanation. From Organic Chemistry Practice Questions: 10 Worked MCQs.

Question 11 mark

1-bromopropane is heated with excess sodium iodide in dry acetone. What is the major organic product?

1-iodopropane is formed by an SN2 substitution: iodide attacks the primary carbon bearing bromine and bromide leaves. Prop-1-ene is an elimination product, but elimination is disfavoured for a primary substrate under these conditions. 2-iodopropane would require rearrangement or substitution at the wrong carbon, and water or hydroxide would be needed for propan-1-ol.

A spoken answer, marked

An examiner's question, answered out loud and marked criterion by criterion. From Organic Chemistry Viva Questions: Practical Practice Guide.

Oral — Reduction of acetophenoneMarked

Examiner

Acetophenone is treated with sodium borohydride, followed by aqueous work-up. What product forms, how does the mechanism proceed, and what stereochemical outcome do you expect?

2:213:00Mark answer
78%Reduction of acetophenone — marked78/100 · Developing · 2:21 spoken of 3:00
Product and functional-group change5/5

Identifies 1-phenylethanol and reduction of the ketone to a secondary alcohol.

ImproveName the product before describing the steps.

Mechanistic reasoning4/5

Explains hydride attack at the carbonyl carbon and formation of an alkoxide.

ImproveShow that the C=O pi electrons move onto oxygen.

Stereochemical outcome3/5

Recognises formation of a stereogenic carbon but does not explain why both faces can be attacked.

ImproveExplain that the carbonyl is planar and the reagent is achiral, so attack on either face gives a racemic mixture.

Conditions and work-up4/5

Mentions aqueous work-up but does not say that it protonates the alkoxide.

ImproveState that protonation of the alkoxide gives the alcohol.

A strong answerAcetophenone is reduced to 1-phenylethanol, a secondary alcohol. A hydride from borohydride attacks the electrophilic carbonyl carbon, and the C=O pi electrons move onto oxygen to form an alkoxide. Aqueous work-up protonates that alkoxide. The product carbon bearing OH is stereogenic. Because the carbonyl is planar and the reagents are achiral, attack on either face gives a racemic mixture.

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